y^'=1-0.4y

Lösung

y^{^{'}} = 1 - 0.4 y

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

Schritte zur Lösung

y^{'} (t) = 1 - 0.4 y

Solve separable ODE:

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

y^{^{'}} = \frac{8 x ^{3} + 1}{3 y ^{2}}

\frac{d y}{d x} = \frac{5 x}{e ^{y}}

\frac{d v}{d t} = - 2 v

\frac{x ^{2} - 9}{x} \frac{d y}{d x} + y = 0

\frac{d y}{d x} = - \frac{3}{7} x^{9} y^{8}