((5y)/3)y^'=x

Lösung

(\frac{5 y}{3}) y^{^{'}} = x

y = \frac{3 x ^{2} + c _{1}}{5}, y = - \frac{3 x ^{2} + c _{1}}{5}

Schritte zur Lösung

(\frac{5 y}{3}) y^{'} (x) = x

Solve separable ODE:

y = \frac{3 x ^{2} + c _{1}}{5}, y = - \frac{3 x ^{2} + c _{1}}{5}

y = \frac{3 x ^{2} + c _{1}}{5}, y = - \frac{3 x ^{2} + c _{1}}{5}

y^{^{'}} + 16 y = 80

y^{^{'}} = 0.8 (y - 250)

3 y^{^{'}} - 6 y = 1

y = x^{10} \frac{d y}{d x}

2 x y - \frac{d y}{d x} - x = 0