y^'+(x^2-2)y=0

Lösung

y^{^{'}} + (x^{2} - 2) y = 0

y = e^{- \frac{x ^{3}}{3} + 2 x + c_{1}}

Schritte zur Lösung

y^{'} (x) + (x^{2} - 2) y = 0

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + 2 x + c_{1}}

y = e^{- \frac{x ^{3}}{3} + 2 x + c_{1}}

y^{^{'}} = \frac{7 x}{y + x ^{2} y}, y (0) = - 13

y^{^{'}} = (x - 1) (y - 2)

y^{^{'}} = \frac{y + 15}{9 t + 238}

y^{^{'}} - 12 \cdot x \cdot y = 9 x

x y^{^{'}} - y = 5