(dy)/(dx)=(3x+5xy^2)

解答

\frac{d y}{d x} = (3 x + 5 x y^{2})

y = \frac{3 tan ( \frac{15 ( x ^{2} + c _{1} )}{2} )}{5}

求解步骤

\frac{d y}{d x} = (3 x + 5 x y^{2})

求解可分离方程:

y = \frac{3 tan ( \frac{15 ( x ^{2} + c _{1} )}{2} )}{5}

y = \frac{3 tan ( \frac{15 ( x ^{2} + c _{1} )}{2} )}{5}

2 y y^{^{'}} = 15 t^{2}, y (0) = 8

x y^{2} d x + e^{x} d y = 0, y = \frac{1}{2}

x y^{^{'}} = y, y (a) = b

\frac{d y}{d x} = 2 x (1 - y)

y^{^{'}} = e^{3 x - 2 y} + x^{2} e^{- 2 y}