(dy)/(dx)=y^2+1,y(0)=0

Lösung

\frac{d y}{d x} = y^{2} + 1, y (0) = 0

y = tan (x)

Schritte zur Lösung

\frac{d y}{d x} = y^{2} + 1

Solve separable ODE:

y = tan (x)

y = tan (x)

\frac{d p}{d t} = 2 pt, p (1) = 6

y^{^{'}} + 3 y = 13, y (0) = 0

y^{^{'}} + x^{2} y = 0, y (0) = 2

x^{^{'}} = x \cdot (1 - x)

\frac{d y}{d x} = 16 x y