y^'=tan(y)x

Lösung

y^{^{'}} = tan (y) x

y = arcsin (e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn

Schritte zur Lösung

y^{'} (x) = tan (y) x

Solve separable ODE:

y = arcsin (e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn

y = arcsin (e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{\frac{x ^{2}}{2} + c_{1}}) + 2 πn

\frac{d y}{d x} = x y^{2} sin (x)

y^{^{'}} = 2 - 0.1 y, y (0) = 0

x^{^{'}} = \frac{1 + x ^{2}}{1 + t ^{2}}

e^{x} d x - 2 y d y = 0

\frac{d y}{d x} = 1 + y^{2}