y^'+4xy-(8x)/(y^3)=0

Lösung

y^{^{'}} + 4 x y - \frac{8 x}{y ^{3}} = 0

y = 4 e^{- 8 x^{2} - c_{1}} + 2, y = - 4 e^{- 8 x^{2} - c_{1}} + 2

Schritte zur Lösung

y^{'} (x) + 4 x y - \frac{8 x}{y ^{3}} = 0

Solve separable ODE:

y = 4 e^{- 8 x^{2} - c_{1}} + 2, y = - 4 e^{- 8 x^{2} - c_{1}} + 2

y = 4 e^{- 8 x^{2} - c_{1}} + 2, y = - 4 e^{- 8 x^{2} - c_{1}} + 2

\frac{d y}{d x} = \frac{3 x - 5}{y - 2}

y^{^{'}} = 4 x^{2} y + 5 x y, y (1) = 1

(y) = y^{^{'}}

y^{3} - y^{^{'}} = 0

\frac{d y}{d x} = y \cdot x^{2} - 1.1 \cdot y