x^'=x(1-x),x(0)=10

Lösung

x^{^{'}} = x (1 - x), x (0) = 10

x = \frac{10 e ^{t}}{- 9 + 10 e ^{t}}

Schritte zur Lösung

x^{'} (t) = x (1 - x)

Solve Bernoulli ODE:

x = \frac{10 e ^{t}}{- 9 + 10 e ^{t}}

x = \frac{10 e ^{t}}{- 9 + 10 e ^{t}}

x^{6} y^{^{'}} - 13 x^{5} y = 0

\frac{d v}{d t} = 80 - \frac{5}{100} v

y d x - x d y = x d y

y^{^{'}} = 1 + x + y + x y, y (0) = 0

x^{3} + 4 y \frac{d y}{d x} = 0