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Popular >

y^'x=cos^2(y)

Solution

y^{^{'}} x = cos^{2} (y)

Solution

y = arctan (ln (x) + c_{1}) + πn

Solution steps

y^{'} (x) x = cos^{2} (y)

Solve separable ODE:

y = arctan (ln (x) + c_{1}) + πn

y = arctan (ln (x) + c_{1}) + πn

Graph

Popular Examples

5x(dy)/(dx)+8y=0

5 x \frac{d y}{d x} + 8 y = 0

y^'+y(2xsin(2x)-sin^2(x))=0

y^{^{'}} + y (2 x sin (2 x) - sin^{2} (x)) = 0

(x+1)^2y^'+8(x+1)y^'+12y=0

(x + 1)^{2} y^{^{'}} + 8 (x + 1) y^{^{'}} + 12 y = 0

derivative of x^2+y^2= derivative of 16

\frac{d}{d x} (x^{2} + y^{2}) = \frac{d}{d x} (16)

(dy)/(dx)=(-0.1)/(cos(y)),y(0)= pi/3

\frac{d y}{d x} = \frac{- 0.1}{cos ( y )}, y (0) = \frac{π}{3}

Frequently Asked Questions (FAQ)

What is the solution for y^'x=cos^2(y) ?
The solution for y^'x=cos^2(y) is y=arctan(ln(x)+c_{1})+pin