y^'=7y^{-2},y(0)=3

Lösung

y^{^{'}} = 7 y^{- 2}, y (0) = 3

y = 3 21 t + 27

Schritte zur Lösung

y^{'} (t) = 7 y^{- 2}

Solve separable ODE:

y = 3 21 t + 27

y = 3 21 t + 27

(3 + x^{2}) d y = 2 x y d x

y^{^{'}} = \frac{5 x ^{2} - 1}{5 + 3 y}

y^{^{'}} = e^{2 y} sin (x)

\frac{d y}{d t} = t^{2} y + 1 + y + t^{2}

e^{x + y} y^{^{'}} = x, y (0) = ln (2)