y^'=y+5

Lösung

y^{^{'}} = y + 5

y = e^{t + c_{1}} - 5

Schritte zur Lösung

y^{'} (t) = y + 5

Solve separable ODE:

y = e^{t + c_{1}} - 5

y = e^{t + c_{1}} - 5

(x ln (x^{2})) y^{^{'}} = 2 y

\frac{d y}{d t} + 0.5 t y = 4 t

\frac{d y}{d x} = \frac{y ^{2}}{x}, y (e) = 3

\frac{1}{y} d y = \frac{- x}{1 + x ^{2}} d x

x^{^{'}} = 1 - 3 x + 2 x^{2}