(xy+x)dx+(xy+y)dy=0,x=1

Lösung

(x y + x) d x + (x y + y) d y = 0, x = 1

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

Schritte zur Lösung

(x y + x) d x + (x y + y) d y = 0

Solve separable ODE:

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

\frac{d x}{d y} = \frac{2}{x}

\frac{d x}{d y} y = \frac{1}{3} x^{\frac{3}{2}}

(\frac{y ^{^{'}}}{x}) + y = 1

\frac{d y}{d x} = - 4 x y^{3}

\frac{d v}{d t} = - 0.00353 v^{2} - 3