y^'+y/3 =4

Lösung

y^{^{'}} + \frac{y}{3} = 4

y = - e^{\frac{- t - c _{1}}{3}} + 12

Schritte zur Lösung

y^{'} (t) + \frac{y}{3} = 4

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{3}} + 12

y = - e^{\frac{- t - c _{1}}{3}} + 12

y^{^{'}} x + y = 0

y^{^{'}} - 5 y = 20, y (0) = 0

tan (x) d y - csc (y) d x = 0

6 y^{^{'}} + 3 t^{2} y = 12 t^{2}

\frac{d}{d x} (x^{2} + y^{2}) = \frac{d}{d x} (25)