y^'-(x^2y-y)/(y+1)=0

Lösung

y^{^{'}} - \frac{x ^{2} y - y}{y + 1} = 0

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

Schritte zur Lösung

y^{'} (x) - \frac{x ^{2} y - y}{y + 1} = 0

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

y^{^{'}} \cdot y^{2} = x

y^{^{'}} + y sin (x) = 0

y^{^{'}} + 2 x^{2} y = \frac{2 x ^{2}}{y}

y^{^{'}} + tan (3 x) y = 0, y (0) = 5

2 x y y^{^{'}} - 2 x^{2} + 1 = 0!