2x+4y(dy)/(dx)-c=0

Lösung

2 x + 4 y \frac{d y}{d x} - c = 0

y = \frac{- x ^{2} + c x + c _{1}}{2}, y = - \frac{- x ^{2} + c x + c _{1}}{2}

Schritte zur Lösung

2 x + 4 y \frac{d y}{d x} - c = 0

Solve separable ODE:

y = \frac{- x ^{2} + c x + c _{1}}{2}, y = - \frac{- x ^{2} + c x + c _{1}}{2}

y = \frac{- x ^{2} + c x + c _{1}}{2}, y = - \frac{- x ^{2} + c x + c _{1}}{2}

\frac{d y}{d x} = (y + 5) (2 x + 1)

\frac{d y}{d x} = 0.32 y

\frac{d y}{d x} = (1 + 2 \cdot x) \cdot y

1 + y^{2} d x + x y ln (x) d y = 0

x^{^{'}} = - a x + b