What is the solution for x^'-0.04x=5000 ?

The solution for x^'-0.04x=5000 is x=25e^{(t+c_{1})/(25)}-125000

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x^'-0.04x=5000

x^{^{'}} - 0.04 x = 5000

x = 25 e^{\frac{t + c _{1}}{25}} - 125000

Solution steps

x^{'} (t) - 0.04 x = 5000

Solve separable ODE:

x = 25 e^{\frac{t + c _{1}}{25}} - 125000

x = 25 e^{\frac{t + c _{1}}{25}} - 125000

2 x y d x = (3 - x^{2}) d y, y (1) = 1

\frac{d}{d x} (x^{2} + y^{2}) = 4

\frac{d}{d x} (x^{2} + y^{2}) = 1

\frac{d y}{d x} = \frac{x}{y ^{21}}

d u = - 12 t^{- 4} d t

What is the solution for x^'-0.04x=5000 ?
The solution for x^'-0.04x=5000 is x=25e^{(t+c_{1})/(25)}-125000