3y^2y^'=1+y^3

Lösung

3 y^{2} y^{^{'}} = 1 + y^{3}

y = 3 e^{t + c_{1}} - 1

Schritte zur Lösung

3 y^{2} y^{'} (t) = 1 + y^{3}

Solve separable ODE:

y = 3 e^{t + c_{1}} - 1

y = 3 e^{t + c_{1}} - 1

x^{^{'}} - \frac{2}{t ^{2}} x = \frac{1}{t ^{2}}

\frac{d y}{d x} = 10 + 3 y

2 y^{^{'}} - 0.8 y = 100

y^{^{'}} = - 2 \cdot t \cdot y^{2}

y^{^{'}} = e^{(4 x + 5 y)}