y^'=cos^2(y),y(0)=0

Lösung

y^{^{'}} = cos^{2} (y), y (0) = 0

y = arctan (t) + πn

Schritte zur Lösung

y^{'} (t) = cos^{2} (y)

Solve separable ODE:

y = arctan (t) + πn

y = arctan (t) + πn

+ 2 y d y - ln (t) d t = e^{t} d t

y^{^{'}} = \frac{2 y}{x ^{2} - 1}

\frac{d y}{d x} - \frac{1}{x} y = \frac{1}{x} y^{3}

y^{^{'}} = \frac{1}{x} (1 + y^{2})

y^{^{'}} = 2 y, y (0) = 6