(1+x)y+(1-y)xy^'=0

Lösung

(1 + x) y + (1 - y) x y^{^{'}} = 0

y = - W (- \frac{1}{e ^{x - c_{1}} x})

Schritte zur Lösung

(1 + x) y + (1 - y) x y^{'} (x) = 0

Solve separable ODE:

y = - W (- \frac{1}{e ^{x - c_{1}} x})

y = - W (- \frac{1}{e ^{x - c_{1}} x})

y^{^{'}} = \frac{2 y ^{2} - 9}{( 3 x y )}

\frac{d y}{d x} - x y = 0, x = 0

\frac{d x}{d t} = 3 - x

\frac{x ^{2} ( d y )}{d x} = y - x y

u^{^{'}} = H (t) + 2 (H (t))^{2}