2zuduudu+u^2dz=0

Lösung

2 z u d uu d u + u^{2} d z = 0

z (u) = e^{- 2 u + c_{1}}

Schritte zur Lösung

2 z (u) u d uu d u + u^{2} d z (u) = 0

Solve separable ODE:

z (u) = e^{- 2 u + c_{1}}

z (u) = e^{- 2 u + c_{1}}

\frac{d x}{d t} = \frac{1}{x e ^{t + 9 x}}

\frac{d y}{d x} = \frac{x ^{5} y}{16 - x ^{6}}

y^{^{'}} = \frac{2 y ^{4} - 2}{( 4 x y ^{3} )}

a y - b y^{^{'}} = 0

\frac{d y}{d x} = 7 x + x y