y^'=(cos(x))/(sin(2y))

Lösung

y^{^{'}} = \frac{cos ( x )}{sin ( 2 y )}

y = \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn, y = - \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn

Schritte zur Lösung

y^{'} (x) = \frac{cos ( x )}{sin ( 2 y )}

Solve separable ODE:

y = \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn, y = - \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn

y = \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn, y = - \frac{arccos ( - 2 sin ( x ) - c _{1} )}{2} + πn

\frac{d y}{d x} = 12 x y

y^{^{'}} - a \cdot y = 0

y \frac{d y}{d x} = 9 x (y^{2} + 5)^{3}

y^{^{'}} = - 3 y (x - 1)

y^{^{'}} = - (\frac{1}{2}) y^{2}, y (0) = 0.5