(1+y)dx+(dy)/(x^2-2x)=0

Lösung

(1 + y) d x + \frac{d y}{x ^{2} - 2 x} = 0

y = e^{- \frac{x ^{3}}{3} + x^{2} - c_{1}} - 1

Schritte zur Lösung

(1 + y) d x + \frac{d y}{x ^{2} - 2 x} = 0

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + x^{2} - c_{1}} - 1

y = e^{- \frac{x ^{3}}{3} + x^{2} - c_{1}} - 1

5 y^{4} d y = 6 x d x

\frac{d y}{d x} - 2 y = 3

x \frac{d x}{d t} - t (2 x + 1) = 0

y^{^{'}} = \frac{x y ^{2}}{1 + x ^{2}}

\frac{d y}{d t} + 7 y = 0