y^'-x^3e^{-y}=0

Lösung

y^{^{'}} - x^{3} e^{- y} = 0

y = ln (\frac{x ^{4}}{4} + c_{1})

Schritte zur Lösung

y^{'} (x) - x^{3} e^{- y} = 0

Solve separable ODE:

y = ln (\frac{x ^{4}}{4} + c_{1})

y = ln (\frac{x ^{4}}{4} + c_{1})

y^{^{'}} - 2 x^{2} y = 0

y^{^{'}} - y = 0, y (0) = 3

y^{^{'}} = y (4 x^{6} + 5)

y^{^{'}} = \frac{y}{x + + x}

\frac{d y}{d x} y = x^{2} + 2 x + 3