e^x(x+1)y^2dx+2xe^xy^1dy=0

Lösung

e^{x} (x + 1) y^{2} d x + 2 x e^{x} y^{1} d y = 0

y = e^{- \frac{1}{2} (x + l n (x)) + c_{1}}

Schritte zur Lösung

e^{x} (x + 1) y^{2} d x + 2 x e^{x} y^{1} d y = 0

Solve separable ODE:

y = e^{- \frac{1}{2} (x + l n (x)) + c_{1}}

y = e^{- \frac{1}{2} (x + l n (x)) + c_{1}}

3 (2 + x^{2}) \frac{d y}{d x} = 2 x y (y^{3} - 1)

y^{^{'}} = 1 + 0.001 y^{2}

x^{^{'}} = 8 x + 3

\frac{d y}{d t} = k y, y (0) = y

\frac{d y}{d x} = - \frac{y ^{2}}{e}