(x-13)(x-3)y^'=y

Lösung

(x - 13) (x - 3) y^{^{'}} = y

y = \frac{c _{1} 10 x - 13}{10 x - 3}

Schritte zur Lösung

(x - 13) (x - 3) y^{'} (x) = y

Solve separable ODE:

y = \frac{c _{1} 10 x - 13}{10 x - 3}

y = \frac{c _{1} 10 x - 13}{10 x - 3}

x d y - (y + 4) d x = 0

\frac{d y}{d x} = 14 e^{5 x - y}, y (0) = 0

\frac{d y}{d t} = \frac{( 3 t ^{2} + 4 t + 2 )}{2 ( y - 1 )}

y^{^{'}} - x (y - 1) = 0

y^{^{'}} = x + x y + 1 + y