3y^'+2y=7,y(0)=2

Lösung

3 y^{^{'}} + 2 y = 7, y (0) = 2

y = - \frac{3 e ^{- \frac{2 t}{3}}}{2} + \frac{7}{2}

Schritte zur Lösung

3 y^{'} (t) + 2 y = 7

Solve separable ODE:

y = - \frac{3 e ^{- \frac{2 t}{3}}}{2} + \frac{7}{2}

y = - \frac{3 e ^{- \frac{2 t}{3}}}{2} + \frac{7}{2}

2 cos (y^{2}) d x - x y sin (y^{2}) d y = 0

\frac{d y}{d x} + \frac{1 - y ^{2}}{1 - x ^{2}} = 0

\frac{d y}{d x} y^{5} = x^{6}

2 x y (y^{^{'}}) = 3

y^{^{'}} = e^{4 x - y}