(dy)/(dt)=t^{1/2}y^2

Lösung

\frac{d y}{d t} = t^{\frac{1}{2}} y^{2}

y = - \frac{3}{2 t ^{\frac{3}{2}} + c _{1}}

Schritte zur Lösung

\frac{d y}{d t} = t^{\frac{1}{2}} y^{2}

Solve separable ODE:

y = - \frac{3}{2 t ^{\frac{3}{2}} + c _{1}}

y = - \frac{3}{2 t ^{\frac{3}{2}} + c _{1}}

4 x^{2} + x^{2} v^{2} d x - 2 x^{3} v d v = 0

\frac{d N}{d t} = k (650 - N)

y^{^{'}} = (\frac{y ^{2}}{( y - 1 )})

\frac{d y}{d x} = 1 - (\frac{y}{100})

y^{^{'}} = (\frac{x}{y})^{2}