y^'=(xy)/(1+x^2)

Lösung

y^{^{'}} = \frac{x y}{1 + x ^{2}}

y = c_{1} 1 + x^{2}

Schritte zur Lösung

y^{'} (x) = \frac{x y}{1 + x ^{2}}

Solve separable ODE:

y = c_{1} 1 + x^{2}

y = c_{1} 1 + x^{2}

(x^{2} + 9) u^{^{'}} + 2 x H (x) = 0

y^{^{'}} tan (x) - y = 0

- 4 y^{^{'}} = 1 + x + y + x y

(8 + y) y^{^{'}} = sin (6 + x)

\frac{d x}{d t} = 14 - 0.56 x, t (0) = 130