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Beliebt Rechnen >

y^'+2xy^2=0,y(1/2)=-4

Lösung

y^{^{'}} + 2 x y^{2} = 0, y (\frac{1}{2}) = - 4

Lösung

y = - \frac{2}{- 2 x ^{2} + 1}

Schritte zur Lösung

y^{'} (x) + 2 x y^{2} = 0

Solve separable ODE:

y = - \frac{2}{- 2 x ^{2} + 1}

y = - \frac{2}{- 2 x ^{2} + 1}

Graph

Beliebte Beispiele

y^'csc(t)=(-y^{15})/(14)

y^{^{'}} csc (t) = \frac{- y ^{15}}{14}

(dx)/(dt)= 1/(xe^{t+7x)}

\frac{d x}{d t} = \frac{1}{x e ^{t + 7 x}}

(ln(y))^6dy=x^6ydx,y(1)=e^2

(ln (y))^{6} d y = x^{6} y d x, y (1) = e^{2}

(dy)/(dx)=10e^x*y^2

\frac{d y}{d x} = 10 e^{x} \cdot y^{2}

2yy^'=18t^2,y(0)=5

2 y y^{^{'}} = 18 t^{2}, y (0) = 5