(dy)/(dt)=e^{t+y},y(0)=0

Lösung

\frac{d y}{d t} = e^{t + y}, y (0) = 0

y = - ln (- e^{t} + 2)

Schritte zur Lösung

\frac{d y}{d t} = e^{t + y}

Solve separable ODE:

y = - ln (- e^{t} + 2)

y = - ln (- e^{t} + 2)

x y d x + (10 x y + x) d y = 0

x \frac{d y}{d x} = y tan (ln (y))

\frac{d y}{d t} = y^{2} (8 + t)

y^{^{'}} y = y^{2}

\frac{d y}{d x} = \frac{x y ^{2}}{x}