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Popular >

dy+(x^2-1)ydx=0

Solution

d y + (x^{2} - 1) y d x = 0

Solution

y = e^{- \frac{x ^{3}}{3} + x + c_{1}}

Solution steps

d y + (x^{2} - 1) y d x = 0

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + x + c_{1}}

y = e^{- \frac{x ^{3}}{3} + x + c_{1}}

Graph

Popular Examples

(2xy^2+x/(y^2))dx+4x^2ydy=0

(2 x y^{2} + \frac{x}{y ^{2}}) d x + 4 x^{2} y d y = 0

sin(y)cos(x)y^'=-cos(y)sin(x)

sin (y) cos (x) y^{^{'}} = - cos (y) sin (x)

(dy)/(dt)=(2t)/(y+yt^2),y(2)=3

\frac{d y}{d t} = \frac{2 t}{y + y t ^{2}}, y (2) = 3

f^'(x)=(x^2)/((f(x))^2),f(1)=2

f^{^{'}} (x) = \frac{x ^{2}}{( f ( x ) ) ^{2}}, f (1) = 2

y^{^{'}} = 7 x y^{87}

Frequently Asked Questions (FAQ)

What is the solution for dy+(x^2-1)ydx=0 ?
The solution for dy+(x^2-1)ydx=0 is y=e^{-(x^3)/3+x+c_{1}}