y^{''}+3y^'-4y=12

Lösung

y^{^{''}} + 3 y^{^{'}} - 4 y = 12

y = c_{1} e^{t} + c_{2} e^{- 4 t} - 3

Schritte zur Lösung

y^{''} (t) + 3 y^{'} (t) - 4 y = 12

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- 4 t} - 3

y = c_{1} e^{t} + c_{2} e^{- 4 t} - 3

y^{^{''}} + 2 y^{^{'}} + y = x^{2} e^{x}

y^{^{''}} - 6 y^{^{'}} + 5 y = - 1 + 5 x

y^{^{''}} - 6 y^{^{'}} + 9 y = 8 e^{3 x}

y^{^{''}} + 4 y = 8 tan^{2} (2 x)

y^{^{''}} + 4 y^{^{'}} = 8