y^{'''}+y^{''}=2x+5

Lösung

y^{^{'''}} + y^{^{''}} = 2 x + 5

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2}

Schritte zur Lösung

y^{'''} (x) + y^{''} (x) = 2 x + 5

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2}

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2}

y^{^{''}} + y = tan (x) + x

y^{^{''}} = - 0.1 y^{^{'}} - x

y^{^{''}} + 4 y = g (t)

y^{^{''}} - 3 y^{^{'}} = 2 x - 3

y^{^{'''}} - 6 y^{^{''}} + 8 y^{^{'}} = sin (2 t) + t^{2} e^{t}