de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

2y^{''}+4y=6t,y(0)=4.9,y^'(0)=0

Lösung

2 y^{^{''}} + 4 y = 6 t, y (0) = 4.9, y^{^{'}} (0) = 0

Lösung

y = 4.9 cos (2 t) - 1.06066 \dots sin (2 t) + \frac{3 t}{2}

Schritte zur Lösung

2 y^{''} (t) + 4 y = 6 t

Solve linear ODE:

y = 4.9 cos (2 t) - 1.06066 \dots sin (2 t) + \frac{3 t}{2}

y = 4.9 cos (2 t) - 1.06066 \dots sin (2 t) + \frac{3 t}{2}

Graph

Beliebte Beispiele

y^{''}-5y^'+6y=24

y^{^{''}} - 5 y^{^{'}} + 6 y = 24

(d^2y)/(dx^2)-5(dy)/(dx)+4y=4

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 4 y = 4

y^{''}+9y=18(sec(3x))^3

y^{^{''}} + 9 y = 18 (sec (3 x))^{3}

3y^{''}+192.08y=48.02cos(8t)

3 y^{^{''}} + 192.08 y = 48.02 cos (8 t)

y^{''}-2y^'-24y=16-(x+2)e^{4x}

y^{^{''}} - 2 y^{^{'}} - 24 y = 16 - (x + 2) e^{4 x}