What is the derivative of x^3+x^2-x ?

The derivative of x^3+x^2-x is 3x^2+2x-1

What is the first derivative of x^3+x^2-x ?

The first derivative of x^3+x^2-x is 3x^2+2x-1

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\frac{d}{d x} (x^{3} + x^{2} - x)

3 x^{2} + 2 x - 1

Solution steps

\frac{d}{d x} (x^{3} + x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 3 x^{2} + 2 x - 1

x \to - 2 lim (\frac{- 9}{x ^{2}})

x \to \infty lim ((5) 66666)

y^{^{''}} + 6 y^{^{'}} + 25 y = 100, y (0) = 0, y^{^{'}} (0) = 0

\frac{\partial}{\partial x} (- e^{x} ln (y))

in v erse l a pl a ce e^{2 s}

What is the derivative of x^3+x^2-x ?
The derivative of x^3+x^2-x is 3x^2+2x-1
What is the first derivative of x^3+x^2-x ?
The first derivative of x^3+x^2-x is 3x^2+2x-1