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Beliebt Rechnen >

0.5q^{''}+20q^'+1/(0.0025)q=100

Lösung

0.5 q^{^{''}} + 20 q^{^{'}} + \frac{1}{0.0025} q = 100

Lösung

q (t) = e^{- 20 t} (c_{1} cos (20 t) + c_{2} sin (20 t)) + 0.25

Schritte zur Lösung

0.5 q^{''} (t) + 20 q^{'} (t) + \frac{1}{0.0025} q (t) = 100

Solve linear ODE:

q (t) = e^{- 20 t} (c_{1} cos (20 t) + c_{2} sin (20 t)) + 0.25

q (t) = e^{- 20 t} (c_{1} cos (20 t) + c_{2} sin (20 t)) + 0.25

Graph

Beliebte Beispiele

x^{''}+16x=14cos(3t)

x^{^{''}} + 16 x = 14 cos (3 t)

y^{''}-2y^'+y=t*e^t

y^{^{''}} - 2 y^{^{'}} + y = t \cdot e^{t}

y^{''}+y^'=x^2e^x

y^{^{''}} + y^{^{'}} = x^{2} e^{x}

(D^2-D-2)y=6e^{(-t)/2}

(D^{2} - D - 2) y = 6 e^{\frac{- t}{2}}

y^{''}+y^'=2sin(t),y(0)=0,y^'(0)=-4

y^{^{''}} + y^{^{'}} = 2 sin (t), y (0) = 0, y^{^{'}} (0) = - 4