y^{''}+25y=20sec(5t)

Lösung

y^{^{''}} + 25 y = 20 sec (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{4}{5} ln (cos (5 t)) cos (5 t) + 4 t sin (5 t)

Schritte zur Lösung

y^{''} (t) + 25 y = 20 sec (5 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{4}{5} ln (cos (5 t)) cos (5 t) + 4 t sin (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{4}{5} ln (cos (5 t)) cos (5 t) + 4 t sin (5 t)

y^{^{''}} - 1 y = tan (x)

y^{^{'''}} + y^{^{''}} - 4 = 0

y^{^{''}} - 8 y^{^{'}} - 4 y - 2 = 2 x

((d^{2}) - 1) y = x sin (x) + (1 + x^{2}) e^{x}

y^{^{''}} - 5 y^{^{'}} + 6 y = g (x)