What is the solution for y^{''}+36y=cos(4x) ?

The solution for y^{''}+36y=cos(4x) is y=c_{1}cos(6x)+c_{2}sin(6x)+1/20 cos(4x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+36y=cos(4x)

y^{^{''}} + 36 y = cos (4 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{1}{20} cos (4 x)

Solution steps

y^{''} (x) + 36 y = cos (4 x)

Solve linear ODE:

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{1}{20} cos (4 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{1}{20} cos (4 x)

\frac{d ^{2} y}{d x ^{2}} + y = x sin (2 x)

5 y^{^{''}} - 4 y^{^{'}} + 3 y = x

y^{^{''}} + 4 y = 3 x^{2}

x^{^{''}} + x^{^{'}} + 4 x = - 3

10 y^{^{''}} + 1000 y = 160 cos (8 t), y (0) = 0

What is the solution for y^{''}+36y=cos(4x) ?
The solution for y^{''}+36y=cos(4x) is y=c_{1}cos(6x)+c_{2}sin(6x)+1/20 cos(4x)