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Beliebt Rechnen >

20y^{''}+9y^'+x=0,y(0)=0,y^'(0)=3

Lösung

20 y^{^{''}} + 9 y^{^{'}} + x = 0, y (0) = 0, y^{^{'}} (0) = 3

Lösung

y = \frac{4460}{729} - \frac{4460}{729} e^{- \frac{9 x}{20}} - \frac{x ^{2}}{18} + \frac{20 x}{81}

Schritte zur Lösung

20 y^{''} (x) + 9 y^{'} (x) + x = 0

Solve linear ODE:

y = \frac{4460}{729} - \frac{4460}{729} e^{- \frac{9 x}{20}} - \frac{x ^{2}}{18} + \frac{20 x}{81}

y = \frac{4460}{729} - \frac{4460}{729} e^{- \frac{9 x}{20}} - \frac{x ^{2}}{18} + \frac{20 x}{81}

Graph

Beliebte Beispiele

solvefor d,d(x)=sqrt((2x^3+1)/(x^6))

so l v e f or d, d (x) = \frac{2 x ^{3} + 1}{x ^{6}}

y^{''}+9y=18cos(3x)

y^{^{''}} + 9 y = 18 cos (3 x)

D^{2} y = 81 y

y^{''}-y^'-6y=50sin(x)-5e^{-2x}

y^{^{''}} - y^{^{'}} - 6 y = 50 sin (x) - 5 e^{- 2 x}

(d^2x)/(dt^2)+2(dx)/(dt)+5x=1

\frac{d ^{2} x}{d t ^{2}} + 2 \frac{d x}{d t} + 5 x = 1