de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{''}+8y^'+16=0,y(0)=1,y^'(0)=0

Lösung

y^{^{''}} + 8 y^{^{'}} + 16 = 0, y (0) = 1, y^{^{'}} (0) = 0

Lösung

y = 1 + \frac{1}{4} - \frac{1}{4} e^{- 8 t} - 2 t

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 16 = 0

Solve linear ODE:

y = 1 + \frac{1}{4} - \frac{1}{4} e^{- 8 t} - 2 t

y = 1 + \frac{1}{4} - \frac{1}{4} e^{- 8 t} - 2 t

Graph

Beliebte Beispiele

y^{''}-2y^'=6x+6-2e^{4x}

y^{^{''}} - 2 y^{^{'}} = 6 x + 6 - 2 e^{4 x}

y^{''}-4y^'+4y=15sin(x)-35cos(x)

y^{^{''}} - 4 y^{^{'}} + 4 y = 15 sin (x) - 35 cos (x)

y^{''}+3y^'+2y=2x+x^2

y^{^{''}} + 3 y^{^{'}} + 2 y = 2 x + x^{2}

y^{''}-a^2*y+b=0

y^{^{''}} - a^{2} \cdot y + b = 0

y^{''}+4y^'=2e^{-4x}+3sin(2x)

y^{^{''}} + 4 y^{^{'}} = 2 e^{- 4 x} + 3 sin (2 x)