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Beliebt Rechnen >

x^{''}+x=1,x(0)=2,x^'(0)=-1

Lösung

x^{^{''}} + x = 1, x (0) = 2, x^{^{'}} (0) = - 1

Lösung

x = cos (t) - sin (t) + 1

Schritte zur Lösung

x^{''} (t) + x = 1

Solve linear ODE:

x = cos (t) - sin (t) + 1

x = cos (t) - sin (t) + 1

Graph

Beliebte Beispiele

(d^2y)/(dx^2)-4y^'+3y=8e^{-x}+9

\frac{d ^{2} y}{d x ^{2}} - 4 y^{^{'}} + 3 y = 8 e^{- x} + 9

(d^2+9)y=cos^4(x)

(d^{2} + 9) y = cos^{4} (x)

y^{''}-y=2e^{-x}

y^{^{''}} - y = 2 e^{- x}

y^{''}+8y^'+15y=3e^{-3t}

y^{^{''}} + 8 y^{^{'}} + 15 y = 3 e^{- 3 t}

(d^2y)/(dx^2)+y=3cos(2x)

\frac{d ^{2} y}{d x ^{2}} + y = 3 cos (2 x)