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tangent x^2+2xy-y^2+x=12,(3,6)

解答

切线

x^{2} + 2 x y - y^{2} + x = 12, (3, 6)

解答

y = \frac{19}{6} x - \frac{7}{2}

求解步骤

计算

x^{2} + 2 x y - y^{2} + x = 12

的斜率:

\frac{d y}{d x} = \frac{- 2 x - 1 - 2 y}{2 ( x - y )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{19}{6}

找到斜率 m=

\frac{19}{6}

且穿过

(3, 6)

的直线:

y = \frac{19}{6} x - \frac{7}{2}

y = \frac{19}{6} x - \frac{7}{2}

作图

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