de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{''}-y^'=0+2t^2+t-1

Lösung

y^{^{''}} - y^{^{'}} = 0 + 2 t^{2} + t - 1

Lösung

y = c_{1} e^{t} + c_{2} - \frac{2 t ^{3}}{3} - \frac{5 t ^{2}}{2} - 4 t

Schritte zur Lösung

y^{''} (t) - y^{'} (t) = 0 + 2 t^{2} + t - 1

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - \frac{2 t ^{3}}{3} - \frac{5 t ^{2}}{2} - 4 t

y = c_{1} e^{t} + c_{2} - \frac{2 t ^{3}}{3} - \frac{5 t ^{2}}{2} - 4 t

Graph

Beliebte Beispiele

y^{''}-y^'+y=25sin(2x)

y^{^{''}} - y^{^{'}} + y = 25 sin (2 x)

y^{''}-2y^'+y=(e^x)/((1-x)^2)

y^{^{''}} - 2 y^{^{'}} + y = \frac{e ^{x}}{( 1 - x ) ^{2}}

x^{^{''}} = - a^{2} x + b

y^{''}-8y^'+16y=2e^{4t}cos(5t)

y^{^{''}} - 8 y^{^{'}} + 16 y = 2 e^{4 t} cos (5 t)

a^2y^{''}-(a^2+1)y^'+y=x

a^{2} y^{^{''}} - (a^{2} + 1) y^{^{'}} + y = x