derivative of 3x^2+12x+9

解答

\frac{d}{d x} (3 x^{2} + 12 x + 9)

6 x + 12

求解步骤

\frac{d}{d x} (3 x^{2} + 12 x + 9)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (12 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (9) = 0

= 6 x + 12 + 0

化简

= 6 x + 12

\int \frac{1}{36 e ^{- 5 x} + e ^{5 x}} d x

s l o p e in t erce pt (4) (8.8)

\int 9 (9 x + 2) d x

t a y l or sin (2 x), 0.0001

x \to 3 lim ([\frac{8}{8 + 10}])