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Beliebt Rechnen >

y^{''}+3y^'+7y=0

Lösung

y^{^{''}} + 3 y^{^{'}} + 7 y = 0

Lösung

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{19 t}{2}) + c_{2} sin (\frac{19 t}{2}))

Schritte zur Lösung

y^{''} (t) + 3 y^{'} (t) + 7 y = 0

Solve linear ODE:

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{19 t}{2}) + c_{2} sin (\frac{19 t}{2}))

y = e^{- \frac{3 t}{2}} (c_{1} cos (\frac{19 t}{2}) + c_{2} sin (\frac{19 t}{2}))

Graph

Beliebte Beispiele

y^{^{''}} + y^{^{'}} = y

y^{'''}+2y^{''}-19y^'-20y=0

y^{^{'''}} + 2 y^{^{''}} - 19 y^{^{'}} - 20 y = 0

(d^2y)/(dx^2)-6(dy)/(dx)+14y=0

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 14 y = 0

y^{''}-13y^'+30y=0

y^{^{''}} - 13 y^{^{'}} + 30 y = 0

y^{'''}-5y^{''}-y^'+5y=0

y^{^{'''}} - 5 y^{^{''}} - y^{^{'}} + 5 y = 0