y^{''}-2piy^'+pi^2y=0

Lösung

y^{^{''}} - 2 π y^{^{'}} + π^{2} y = 0

y = c_{1} e^{π t} + c_{2} t e^{π t}

Schritte zur Lösung

y^{''} (t) - 2 π y^{'} (t) + π^{2} y = 0

Solve linear ODE:

y = c_{1} e^{π t} + c_{2} t e^{π t}

y = c_{1} e^{π t} + c_{2} t e^{π t}

y^{^{''}} - 2 y - 3 y = 0

4 y^{^{''}} + 16 y^{^{'}} + 25 y = 0

y^{^{''}} - 14 y^{^{'}} + 65 y = 0

y^{^{''''}} - 81 y^{^{''}} = 0

3.5 y^{^{''}} - 5.6 y^{^{'}} + 2.2 y = 0