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Beliebt Rechnen >

16y^{''}+56y^'+130y=0,y(1)=2,y^'(1)=5

Lösung

16 y^{''} + 56 y^{'} + 130 y = 0

Lösung

y = e^{- \frac{7 t}{4}} (c_{1} cos (\frac{9 t}{4}) + c_{2} sin (\frac{9 t}{4}))

Schritte zur Lösung

16 y^{''} (t) + 56 y^{'} (t) + 130 y = 0

Solve linear ODE:

y = e^{- \frac{7 t}{4}} (c_{1} cos (\frac{9 t}{4}) + c_{2} sin (\frac{9 t}{4}))

y = e^{- \frac{7 t}{4}} (c_{1} cos (\frac{9 t}{4}) + c_{2} sin (\frac{9 t}{4}))

Beliebte Beispiele

y^{^{''}} - 324 y = 0

49y^{''}+56y^'+16y=0

49 y^{^{''}} + 56 y^{^{'}} + 16 y = 0

y^{''}+y^'-15y=0

y^{^{''}} + y^{^{'}} - 15 y = 0

y^{''''}-4y^{'''}+5y^{''}-4y^'+4y=0

y^{^{''''}} - 4 y^{^{'''}} + 5 y^{^{''}} - 4 y^{^{'}} + 4 y = 0

(d^2y)/(dx^2)-4(dy)/(dx)-12y=0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} - 12 y = 0