2y^{''}+4y^'-7y=0

Lösung

2 y^{^{''}} + 4 y^{^{'}} - 7 y = 0

y = c_{1} e^{\frac{( - 2 + 3 ) t}{2}} + c_{2} e^{- \frac{( 2 + 3 ) t}{2}}

Schritte zur Lösung

2 y^{''} (t) + 4 y^{'} (t) - 7 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 2 + 3 ) t}{2}} + c_{2} e^{- \frac{( 2 + 3 ) t}{2}}

y = c_{1} e^{\frac{( - 2 + 3 ) t}{2}} + c_{2} e^{- \frac{( 2 + 3 ) t}{2}}

81 y^{^{''''}} = 16 y

y^{^{''}} - 441 y = 0

\frac{d ^{2} x}{d t ^{2}} + 6 \frac{d x}{d t} + 10 x = 0

y^{^{'''}} + 2 y^{^{''}} + 4 y^{^{'}} + 8 y = 0

y^{^{''}} + y = 0, y (0) = 1