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Beliebt Rechnen >

4y^{''}+4y^'+4y=0

Lösung

4 y^{^{''}} + 4 y^{^{'}} + 4 y = 0

Lösung

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Schritte zur Lösung

4 y^{''} (t) + 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Graph

Beliebte Beispiele

5 y^{^{''}} + 5 y = 0

4y^{''}-2y^'-2y=0,y(0)=4,y^'(0)=1

4 y^{^{''}} - 2 y^{^{'}} - 2 y = 0, y (0) = 4, y^{^{'}} (0) = 1

y^{''}+2y^'+10y=0,y(0)=0

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 0

y^{''}+2y^'+y=0,y^1(0)=xe-x

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{1} (0) = x e - x

y^{''}-4y^'-5y=0,y(1)=0

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0