y^{''}+64y=0,y(0)=8,y^'(0)=-4/3

Lösung

y^{^{''}} + 64 y = 0, y (0) = 8, y^{^{'}} (0) = - \frac{4}{3}

y = 8 cos (8 t) - \frac{1}{6} sin (8 t)

Schritte zur Lösung

y^{''} (t) + 64 y = 0

Solve linear ODE:

y = 8 cos (8 t) - \frac{1}{6} sin (8 t)

y = 8 cos (8 t) - \frac{1}{6} sin (8 t)

\frac{d ^{2} x}{d t ^{2}} + 324 \frac{d x}{d t} + 4 x = 0

x^{^{''}} + 5 \cdot x = 0

y^{^{''}} + 121 y = 0

2 y^{^{''}} + 4 y^{^{'}} + 8 y = 0

2 y^{^{''}} - 3 y^{^{'}} + 1 y = 0